Sum Aggr()

[sebastian_fager]

Why dosen't this works? 😕

Sum(aggr( DISTINCT sum({<Attribute = {'M1'}>}ConsumptionPerDay*5) * RecipeShare, ProductID))

It dosen't sum if it's several ProductIDs. It works if there are only one ProductID.

I have also tried:

sum(aggr( sum($(vVariable)),ProductID))

Where $(vVariable) = sum({<Attribute = {'M1'}>}ConsumptionPerDay*5) * RecipeShare

[sunny_talwar]

What is the dimension where you are doing this? Can you may be share a sample to see what might not be working in this.

[swuehl]

I assume RecipeShare does not show a unique, single value per ProductID.

It's equivalent to write your expression as

Sum(aggr( DISTINCT sum({<Attribute = {'M1'}>}ConsumptionPerDay*5) * Only(RecipeShare), ProductID))

Use Aggregation Functions!

Not sure what you intend to calculate, but either apply an aggregation function other than Only() to RecipeShare, or maybe add RecipeShare to the Sum():

=Sum(aggr( DISTINCT sum({<Attribute = {'M1'}>} ConsumptionPerDay*5 * RecipeShare), ProductID))

Or maybe you need to add more dimensions to the aggr() function to allow Only(RecipeShare) to work.

[sebastian_fager]

Hi,

I think i need one more dimension. The RecipeShare is a unique value per ProductID and raw material.

Example:

ProductID     RawMaterialID     RecipeShare     Forecast

5001             28025                    0,2                       10

5001             27051                    0,8                       10

4025              28025                    0,3                      7

4025              23047                    0,5                      7

4025              25045                    0,2                      7

And diffrent ProductID shares the same RawMaterialID. So if i choose raw material 28025 i want to see on a row how much RawMaterial  total i need based on the forecast for the ProductID.

Correct answer for 28025 would be 6,1 (0,2*10+0,3*7).

[swuehl · Accepted solution]

I think I have a different correct result:

RawMaterialID	Sum(Aggr( Only(RecipeShare) * Only(Forecast), RawMaterialID, ProductID))
	4,1
28025	4,1

[sebastian_fager]

Haha, you are correct!

Wonderful! It works great, big thanks!