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arpitkharkia
Creator III
Creator III

Obtain field with maximum value

Please consider the following example:

CategoryValue
A10%
B20%
B22%
A20%

I will be loading the above table directly into Qlik. What I want is to first have an average of Value so that the following table is obtained:

CategoryValue
A15%
B21%

from this now I have to find the name of the category having the highest value. So, from table1 I have to obtain Category B as the answer.

How to perform the above using Set Analysis or/and Back-end scripting?

1 Solution

Accepted Solutions
lironbaram
Partner - Master III
Partner - Master III

hi

for finding the Category with the highest avg

use this expression :

=FirstSortedValue(Category,-aggr(avg(Value),Category))

View solution in original post

6 Replies
lironbaram
Partner - Master III
Partner - Master III

hi

for finding the Category with the highest avg

use this expression :

=FirstSortedValue(Category,-aggr(avg(Value),Category))

Anil_Babu_Samineni

Why can't you create Simple

Num(Avg(Value),'##,##0%')

Capture.PNG

For second one try like below

For Max =FirstSortedValue(Category,Aggr(Num(Avg(Value),'##,##0%'),Category))

For Min =FirstSortedValue(Category,-Aggr(Num(Avg(Value),'##,##0%'),Category))

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful
HirisH_V7
Master
Master

Hi,

Check this

=Num(rangeavg(Aggr(Above(sum(Value),0,rowno()),Category))/Count(Category),'#,##0%')

As Exression in chart  or Table.

-Hirish

HirisH
“Aspire to Inspire before we Expire!”
MK_QSL
MVP
MVP

=FirstSortedValue(Distinct Category,-Aggr(Avg(Value),Category))

or

=FirstSortedValue(Category,-Aggr(Avg(Value),Category))

and if you have more than one category having same average.. you can use below to get more than one category..

=Concat({<Category = {"=Rank(Avg(Value))=1"}>}DISTINCT Category)

surendraj
Specialist
Specialist

Hi Arpit,

I tried this,Its working fine.

=FirstSortedValue({<Category>}Category,-Aggr(max({<Category>}Value),Category))


By using this you can achieve Category B as the answer even if you made the selection on Category it won't change.


--Surendra

arpitkharkia
Creator III
Creator III
Author

Thank you everyone for the help!