Trying to show overtime vs standard hours per week. Need to calculate based on hours per employee

[#1]

I am trying to show a chart that shows Hours per week, and Over time hours per week.

I am running into a problem where I need to tell the expression to take a summary for the week based on the employee, and if that number is over 40 to subtract 40 to get the over time hours.

How can I tell it to do this?

Example:

Employee       Hours per week

1                    30

2                    50

3                    20

4                    60

5                    40

The correct overtime for this example is 30. Standard hours is 170.

Calculating Standard as 40hr/employee would show 200 standard hours and 0 over time.

[swuehl]

What about using two expressions like

=if([Hours per week] >40, [Hours per week]-40)

for overtime hours and

=if([Hours per week] <=40, [Hours per week], 40)

for standard hours?

[#3]

Let me explain more on how my chart is set up. (Overtime is given per employee who works over 40 hours in one week)

Current Dimension: week([Date Payroll])

Expression should be sum(hours) for that week per employee. If one employee works 60 hours that week it should record 20 hours of OT and 40 Standard.

If another employee works 30 hours it should show 0 OT hours and 30 Standard.

Instead I see Total hours=90

Standard (# employees *40)=80

Overtime hours=10

I pretty much need to take a sum of hours per week grouped by the sum employee hours but I do not know how to sum per employee when that is not a dimension

[swuehl]

It should be feasible and not too complicated  using advanced aggregation aggr(), maybe like

= sum( aggr(if(sum(hours) > 40, hours-40), weekPayroll, employee))

for overtime hours.

AFAIR, aggr doesn't take calculated dimensions, so you might need to add a week(DatePayroll) as weekPayroll to your data model.

If you could post a small sample, I believe someone might figure out the correct expression quite fast.

Regards,

Stefan

[#5]

I tried your expression, and I only get "No Data to Display" on the chart.

I will try and come up with a sample that I can post.

[#6]

One slight change to the expression will make it calculate accurately in your sample.

=sum ( aggr(if(sum(Hours) > 40, sum(Hours)-40), [Week Payroll], Employee))

[#7]

That does let it work. Now as a final question that relates to that, how would I use a set analysis for this?

Need to add

{<[Year Payroll]={$(=Year(Today()))}>} so it only pulls info for this year

[#8]

If I recall correctly you can't use aggr with set analysis, so would need to

do something like this:

sum( aggr(if(sum(Hours) > 40 and = year(Today()),

sum(Hours)-40),

, Employee))

[#9]

Um I am guessing you did not mean to post a link there? I am also guessing that the first link should be [Year Payroll]=Year(Today())

[#10]

Interesting, wonder what outlook did this time... let me try this again...

sum( aggr(if(sum(Hours) > 40 and [Year Payroll] = year(Today()), sum(Hours)-40), [Week Payroll], Employee))