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Anonymous
Not applicable

include statement with a variable

Hi,

is there a way to inser a variable path into an include statement ?

I'm trying this:

let my_include = '$include=' & peek('my_path');

$(my_include);

but simply it doesn't work, without any further.

Is it possible to do it ? Help please

Thanks in advance

1 Solution

Accepted Solutions
flipside
Partner - Specialist II
Partner - Specialist II

Hi,

Try it this way ...

let my_include= 'LoadScript.txt';

$(include=$(my_include));

flipside

View solution in original post

2 Replies
flipside
Partner - Specialist II
Partner - Specialist II

Hi,

Try it this way ...

let my_include= 'LoadScript.txt';

$(include=$(my_include));

flipside

Anonymous
Not applicable
Author

THANKS VERY MUCH !!!