topic Re: Creating range in following format in App Development

Creating range in following format

Karahs — Thu, 03 Mar 2016 05:28:02 GMT

hi all,

i have Some random Value and i need to create Range like -

0 - 0.1

0.2 - 0.3

0.4 - 0.5

0.6 - 0.8

0.8 - 1.0

I made Use of Class Function it gives me Following Output

0-0.1

0.1-0.2

0.2-0.3

i don not want repeated Values

Thanks,

Re: Creating range in following format

sunny_talwar — Thu, 03 Mar 2016 11:51:16 GMT

You can use if statement to do it:

If(Value <= 0.1, '0 - 0.1',

If(Value <= 0.3, '0.2 - 0.3',

If(Value <= 0.5, '0.4 - 0.5',

If(Value <= 0.8, '0.6 - 0.8', '0.8 - 1.0'))))

For sorting trouble you can further add a dual function:

If(Value <= 0.1, Dual('0 - 0.1', 1),

If(Value <= 0.3, Dual('0.2 - 0.3', 2),

If(Value <= 0.5, Dual('0.4 - 0.5', 3),

If(Value <= 0.8, Dual('0.6 - 0.8', 4), Dual('0.8 - 1.0', 5)))))

Re: Creating range in following format

Thu, 03 Mar 2016 12:01:10 GMT

I've been meaning to try using IntervalMatch‌for this sort grouping

Am sure it would look nicer than nested IF (no idea if it would function any better!)

Re: Creating range in following format

Anonymous — Thu, 03 Mar 2016 12:16:08 GMT

Intervalmatch() would not help you in creating random buckets like you asked, Either Class() or what Sunny T‌

suggested will work...

For more details check this as well?

Buckets

Re: Creating range in following format

Thu, 03 Mar 2016 13:02:32 GMT

I like the CLASS and ROUND function - will make use of those!

I reckon ROUND is the best bet. I played around with:-

setting an Interval variable:

LET vInterval = 0.1;

Then adding the ROUND function into the load script (i used [iNum] as my number field)

ROUND(iNum-($(vInterval)/2),$(vInterval)) & ' to ' & (ROUND(iNum-($(vInterval)/2),$(vInterval))+($(vInterval)-($(vInterval)/10))) AS [iRound]

that creates groups as:

0.1 to 0.19

0.2 to 0.29

0.3 to 0.39 etc