<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic Re: Help with Max value over dimension in App Development</title>
    <link>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561966#M40933</link>
    <description>&lt;P&gt;Second dimension is [IssueDate.autoCalendar.Year], and now it works with:&lt;BR /&gt;&lt;BR /&gt;Max(Aggr($(v.TotalCost), [IssueDate.autoCalendar.Month], [IssueDate.autoCalendar.Year]))&lt;BR /&gt;&lt;BR /&gt;Thanks a lot for your help Sunny!&lt;/P&gt;</description>
    <pubDate>Wed, 27 Mar 2019 14:43:36 GMT</pubDate>
    <dc:creator>josemaria_cabre</dc:creator>
    <dc:date>2019-03-27T14:43:36Z</dc:date>
    <item>
      <title>Help with Max value over dimension</title>
      <link>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561958#M40931</link>
      <description>&lt;P&gt;Hi,&lt;BR /&gt;&lt;SPAN&gt;I'm having trouble finding month with max value from this set of data:&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="459cabcf0848431c951a399be781bf2c.png" style="width: 790px;"&gt;&lt;img src="https://community.qlik.com/t5/image/serverpage/image-id/8936i29E5A777520FF78E/image-size/large?v=v2&amp;amp;px=999" role="button" title="459cabcf0848431c951a399be781bf2c.png" alt="459cabcf0848431c951a399be781bf2c.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;I'm looking for an expression that returns 8.28 M, but with this expression:&lt;/P&gt;&lt;P&gt;Max( total &amp;lt;[IssueDate.autoCalendar.Month]&amp;gt; aggr( $(v.TotalCost), [IssueDate.autoCalendar.Month]))&amp;nbsp;&lt;/P&gt;&lt;P&gt;I'm getting 12.88 M, (which is the sum of 8.28 M + 4.6 M ...)&lt;BR /&gt;&lt;BR /&gt;How should I modify this expression to return max value from all months, but without aggregating ?&lt;/P&gt;&lt;P&gt;Thanks in advance for your help,&lt;BR /&gt;Jose&lt;/P&gt;</description>
      <pubDate>Sat, 16 Nov 2024 21:10:00 GMT</pubDate>
      <guid>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561958#M40931</guid>
      <dc:creator>josemaria_cabre</dc:creator>
      <dc:date>2024-11-16T21:10:00Z</dc:date>
    </item>
    <item>
      <title>Re: Help with Max value over dimension</title>
      <link>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561963#M40932</link>
      <description>&lt;P&gt;What is the second dimension in your chart? Try this&lt;/P&gt;&lt;PRE&gt;Max(Aggr($(v.TotalCost), [IssueDate.autoCalendar.Month], Dimension2)) &lt;/PRE&gt;</description>
      <pubDate>Wed, 27 Mar 2019 14:37:34 GMT</pubDate>
      <guid>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561963#M40932</guid>
      <dc:creator>sunny_talwar</dc:creator>
      <dc:date>2019-03-27T14:37:34Z</dc:date>
    </item>
    <item>
      <title>Re: Help with Max value over dimension</title>
      <link>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561966#M40933</link>
      <description>&lt;P&gt;Second dimension is [IssueDate.autoCalendar.Year], and now it works with:&lt;BR /&gt;&lt;BR /&gt;Max(Aggr($(v.TotalCost), [IssueDate.autoCalendar.Month], [IssueDate.autoCalendar.Year]))&lt;BR /&gt;&lt;BR /&gt;Thanks a lot for your help Sunny!&lt;/P&gt;</description>
      <pubDate>Wed, 27 Mar 2019 14:43:36 GMT</pubDate>
      <guid>https://community.qlik.com/t5/App-Development/Help-with-Max-value-over-dimension/m-p/1561966#M40933</guid>
      <dc:creator>josemaria_cabre</dc:creator>
      <dc:date>2019-03-27T14:43:36Z</dc:date>
    </item>
  </channel>
</rss>

