topic Re: Calling openApp on a non authorized user in mashup in Integration, Extension & APIs

Calling openApp on a non authorized user in mashup

AKN — Thu, 22 Feb 2024 10:53:39 GMT

Hi,

I have an array of app ids. However if current user is not authorized on the app it gives "Forbidden" error. I don't want to try to open the app if it gives error and continue with next app id.

for (let i = 0; i < appIds.length; i++) { getSheet(appIds[i]); } function getSheet(_appId) { qlik.openApp(_appId, config); }

I've tried the last answer of this thread but still error pops up and for loop breaks:

https://community.qlik.com/t5/Integration-Extension-APIs/Forbidden-app-for-the-current-user-Qlik-Sense-Mashup/m-p/146172

Re: Calling openApp on a non authorized user in mashup

alex_colombo — Thu, 22 Feb 2024 13:36:39 GMT

Hi @AKN , you should be able to manage errors using "on" method and looking for errors. When a user cannot open an app your on error function should be triggered and then you can manage them. Please see this example.

Re: Calling openApp on a non authorized user in mashup

AKN — Thu, 22 Feb 2024 20:41:19 GMT

Thank you, this works!

However whenever console.log("error", _appId) runs ~~it logs all previous app ids that gave an error too~~ it logs all previous app ids even if they didn't give any error. Do you think that's because how on method works or my code is broken somehow?

openApp.on("error", function (error) { console.log("error", _appId); });

For example

if appid = "1" gave an error it logs

"error 1"

and after that appid = "2" gives an error then it logs

"error 1"

"error 2"

appid = "3" doesn't give any error.

appid = "4" gives an error and then:

"error 1"

"error 2"

"error 3"

"error 4"

and so on.

Re: Calling openApp on a non authorized user in mashup

alex_colombo — Fri, 23 Feb 2024 08:46:21 GMT

Your code is ok, this could be a bug. If you want you can open a support case for further investigation. Thanks!