topic StringIndexOutOfBoundsException: String index out of range: 40 how to fix in Talend Studio

StringIndexOutOfBoundsException: String index out of range: 40 how to fix

Anonymous — Thu, 15 Nov 2018 14:14:19 GMT

I have two columns (tmysqloutput) that I will get the value from only one column (tmysqlinput) depends on the condition, when I tried to run with to one column first, everything are working perfectly, but then when I load the expression on the second column, I got this error:

Exception in component tMap_4 (FileExtractAndLoad)
java.lang.StringIndexOutOfBoundsException: String index out of range: 40
at java.lang.String.substring(Unknown Source)

My expression syntax for the column that throwing that error is:

row5.ADDRESS.contains("%TOSL%") ? row5.ADDRESS.substring(0,4): ((row5.ADDRESS.substring((row5.ADDRESS.indexOf("to") + 3),(row5.ADDRESS.indexOf("to") + 10))).replace("-", "").replaceAll("\\D*",""))

While the first one is this:

row5.ADDRESS.contains("%Refer%") ? row5.ADDRESS.substring(0,4): ((row5.ADDRESS.substring((row5.ADDRESS.indexOf("ABC") + 4),(row5.ADDRESS.indexOf("ABC") + 11))).replace("-", "").replaceAll("\\D*",""))

Is there any possible way on how ti fix this? And if there's a way, I need to implement it on both expression?

Thanks!

Re: StringIndexOutOfBoundsException: String index out of range: 40 how to fix

Anonymous — Thu, 15 Nov 2018 14:51:56 GMT

In the second expression you need to change row5.ADDRESS.substring(0,4) to row5.ADDRESS.substring(0,5), since the other numbers all increased by 1 (i.e 3 to 4, and 10 to 11).

Re: StringIndexOutOfBoundsException: String index out of range: 40 how to fix

Anonymous — Thu, 15 Nov 2018 14:53:46 GMT

What do you mean? Sorry, but is that a serious answer?

Re: StringIndexOutOfBoundsException: String index out of range: 40 how to fix

Anonymous — Thu, 15 Nov 2018 21:22:56 GMT

Yes, although on looking at your post again, I think I switched the expression that works with the one that doesn't. The one that works is:

row5.ADDRESS.contains("%Refer%") ? row5.ADDRESS.substring(0,4): ((row5.ADDRESS.substring((row5.ADDRESS.indexOf("ABC") + 4),(row5.ADDRESS.indexOf("ABC") + 11))).replace("-", "").replaceAll("\\D*",""))

correct? And for the second expression, you copied this and updated the "index numbers", right?

row5.ADDRESS.contains("%TOSL%") ? row5.ADDRESS.substring(0,4): ((row5.ADDRESS.substring((row5.ADDRESS.indexOf("to") + 3),(row5.ADDRESS.indexOf("to") + 10))).replace("-", "").replaceAll("\\D*",""))

I think the issue is with row5.ADDRESS.substring(0,4); the row5.ADDRESS.contains("%TOSL%") can return a string of length 3 ("TOSL"), so it should be row5.ADDRESS.substring(0,3). Otherwise, when it returns "TOSL", you're trying to read position 4 in a zero-indexed string, which is out of bounds.

Hope this helps.

Re: StringIndexOutOfBoundsException: String index out of range: 40 how to fix

Anonymous — Fri, 16 Nov 2018 04:24:26 GMT

@DVSCHWAB

Thanks for taking time to response on my question, I fixed this by doing the code below:

row5.ADDRESS.contains("%REFER%") ? row5.ADDRESS.trim(): ((row5.ADDRESS.substring(row5.ADDRESS.indexOf("ABC") +4, Math.min(row5.ADDRESS.indexOf("ABC") + 11, row5.ADDRESS.length())).replace("-","").replaceAll("\\D","")))

The key is to use the "Math.min and length"