topic Re: Doubts in understanding the ceil and floor functions in QlikView

Doubts in understanding the ceil and floor functions

Sun, 14 Apr 2013 16:19:33 GMT

Hi to all,

From qlikview help i knew how the ceil and floor functions works,but still i have some doubts in these two functions.

Ex1.ceil( 1.1 , 1 , 0.5 ) returns 1.5

ex2.Ceil(2.6, 0.25) returns 2.75

internally how ceil() works in above 2 examples

ex1.floor( 3.88 , 5 ) returns 0
ex2.floor( 1.1 , 1 , 0.5 ) returns 0.5
ex3.Floor(2.6, 0.25) returns 2.5

Internally how floor() works in above 3 examples.

Prior to this posting i had searched in the google,qlikview reference manual and in the book qlikview 11 for developers.But i didn't get any thing.

Can any one please helpme in the layman language as early as possible.

Thanks in advance.

Re: Doubts in understanding the ceil and floor functions

nagaiank — Sun, 14 Apr 2013 21:17:04 GMT

ceil(x [ , base [ , offset ]])

Rounding of x upwards to the nearest multiple of base with an offset of offset. The result is a number.

Examples:

ceil( 1.1 , 1 , 0.5 ) returns 1.5

Multiples of 1 are 0, 1, 2, 3, 4

If apply the offset 0.5, you get 0.5, 1.5, 2.5, 3.5, 4.5

The nearest higher number for 1.1 is 1.5 and so ceil returns 1.5

floor(x [ , base [ , offset ]])

Rounding of x downwards to the nearest multiple of base with an offset of offset. The result is a number.

Examples:

floor( 3.88 , 5 ) returns 0

multiple of 5 are 0,5,10,15

In this list, the nearest lower number for 3.88 is 0 and so floor() returns 0

Hope this helps.

Re: Doubts in understanding the ceil and floor functions

swuehl — Sun, 14 Apr 2013 22:22:23 GMT

floor(), ceil() [and not to forget round()] all have the same possible arguments:

ceil(x [ , base [ , offset ]])

Rounding of x upwards to the nearest multiple of base with an offset of offset. The result is a number.

floor(x [ , base [ , offset ]])

Rounding of x downwards to the nearest multiple of base with an offset of offset. The result is a number.

round( x [ , base [ , offset ]])

Rounding of x upwards or downwards to the nearest multiple of base with an offset of offset. The result is a number. If x is exactly in the middle of an interval, it is rounded upwards.

'x' is your input number. 'offset' is the number your intervals start from. base is the interval increment.

So ex2.floor( 1.1 , 1 , 0.5 ) creates intervals like [0.5, 1.5]; [1.5, 2.5]; [2.5, 3.5] ...

If your input is 1.1, the first interval is the matching one. floor() now returns the lower limit and ceil() the upper limit of the matching interval.

Hope this helps,

Stefan

Re: Doubts in understanding the ceil and floor functions

Joaquin_Lazaro — Fri, 19 Apr 2013 14:34:50 GMT

Hi:

Good help from krishnamoorthy & swuehl .

... but with QV 11 SR2 64-bits there is a problem with Round and Floor, both not working as expected.

See Support cases 00170986 & 00170987.

I could write a little trick but of course have other problems behind!!!

Re: Doubts in understanding the ceil and floor functions

Tue, 25 Jun 2013 13:53:58 GMT

Hi ,

let x=ceil(5.3,2,8);

As per your logic ,

Multiples of 2 are 0,2,4,6,8

If apply the offset 8 you get 8,10,12....

output will be 8 .

But i'm getting 6. Do you know why ? Am i missing anything ??

Thanks and Regards

Satti

Re: Doubts in understanding the ceil and floor functions

swuehl — Tue, 25 Jun 2013 21:09:21 GMT

The intervals are not only created by using positive integral numbers as factor for the increments, but also negative. So intervals start not only from 0,2,4,6,8,... but from ...-4, -2,0,2,4,6 ....

So 6 is indeed the nearest interval upper limit to 5.3.

Re: Doubts in understanding the ceil and floor functions

Thu, 27 Jun 2013 08:10:16 GMT

Thanks and Perfect ..

Re: Doubts in understanding the ceil and floor functions

Akbar — Mon, 15 Jun 2020 20:43:26 GMT

thanks for this post

Re: Doubts in understanding the ceil and floor functions

Vijayqlik4171 — Wed, 15 Sep 2021 06:02:28 GMT

ceil(5.3,2,8) = 6

sloution

intially =0

0,2,6,8

your value is 5.3

ceil will take nearest up value that is 6

Re: Doubts in understanding the ceil and floor functions

Vijayqlik4171 — Wed, 15 Sep 2021 17:13:26 GMT

one more example detail

ceil(5.3,6,3)

5.3= input

6= increment (increment start with"0")

3= base

solution = 0(increment )+3(base)=3, 6(increment ) +3(base)=9, 12(increment )+3(base)=15

final input =5.3

nearest for 5.3 = 9