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Hello All,
I want the correct expression containing the AGGR Function for the given query.
Tried a few things but it didn't work out.
I'm posting the example below.
Sum[Count( Distinct (mobilecode))/Count(Distinct (routecode))]
Where mobilecode and routecode are field names.
Thanks In Advance.
Hi Chanin,
Please use the below code
Sum(Aggr((Sum([mobilecode])),[routecode]))
Regards,
Rajesh R. S.
Hi,
Assuming that you are counting the number of mobile codes in given routecode.
Below is the AGGR function.
=Aggr(count(DISTINCT mobilecode),routecode)
SUM(Aggr(COUNT(Distinct mobilecode)/COUNT(Distinct routecode),YourDimensionField1,YourDimensionField2))
or
Avg(Aggr(COUNT(Distinct mobilecode)/COUNT(Distinct routecode),YourDimensionField1,YourDimensionField2))
Normally an expression like this would be the right one:
Sum( Aggr( Count(DISTINCT mobilecode) / Count(DISTINCT routecode) , <DIM1> [, <DIM2 , ... ]) )
<DIM1> is a field that is the first grouping level.
[<DIM2>, ....] is an optional list of one or more grouping levels you need or want.
Whether this will work in the context you intend to use it is hard for me to say.
The thing that Aggr introduce is that you aggregate over one or more dimension....
So it is a grouping level you have to select for the Aggr function to work. The result of an Aggr might be 0 or more values. That's why you have to do an aggregation afterwards to be sure that you can display or present the results of the Aggr.
Try:
Sum(aggr(Count( Distinct (mobilecode))/Count(Distinct (routecode)), Dim1, Dim2))
whereby Dim1, Dim2 are the dimensions in your chart respectively those dimensions against the calculation should be run.
- Marcus
Thnks for the reply
What to add in the dimension fields . I'm a bit confused in that ??
so can this be answered without using the AGGR function ? If yes could you please post the answer .
Where are you using this expression? In chart or straight table?
You need to use those Dimensions here !
So can the answer be found out without using the AGGR function? If yes could you please post the answer .