Show all values of a dimension on a map layer regardless of current selections

[morenoju]

Hi folks,

I have a table with ids and geometries: item_id, location

I want to show all items on a map regardless of the user selection on item_id. I thought I could do this by configuring the dimension as only({1}item_id) but I get an invalid dimension error.

I've thought of using alternate states, but then if the user picks an item from the map, I can't see the selection in other charts.

How can I show all items on the map regardless of the current selections?

[JordyWegman]

Hi Morenoju,

I think the only way is to disable the selections, but you can't overrule selections being made in the other objects. The current map will always show it.

Jordy

Climber

[morenoju]

Thanks Jordy. But isn't there a way to show all items on the map layer regardless the selections being made in other objects? This is something we often do in tables and charts.

I tried to use an alternate state

=only({AlternateState2}[item_id])

But it also gives invalid dimension error.

@Patric_Nordstrom  , maybe you have a visualization trick to achieve this? 🙂

Thanks!

[morenoju]

For now, what I'm going to be doing is to concatenate the locations as a multistring:

LOAD
0 as item_id,
'[' & concat(location,',') & ']' as location,
RESIDENT items;

[Patric_Nordstrom]

Yes, the easiest way is to use set analysis to ignore selections. Make sure the set expression is on all the measures: location, color, label in the layer etc etc.

Dimension = item

Location = only({1} location)

Thanks,

Patric