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Anonymous
Not applicable

Compare Same Day Last Year and Calculate Percentage Growth

Objective: To calculate year over year growth by day. If the user selects April 2018, it would compare each day in April with the same day in the previous year. The same day being the number, not the day of the week.

Dimension: MonthDay

Expression: (2018 Units - 2017 Units) / 2017 Units

=(((SUM(b50_transientunits))

-

(Sum({<b50_Year= {$(=(b50_Year-1))}, b50_Month = {$(=(b50_Month))}, b50_Day = {$(=(b50_Day))} >}b50_transientunits))))

/

(Sum({<b50_Year= {$(=(b50_Year-1))}, b50_Month = {$(=(b50_Month))}, b50_Day = {$(=(b50_Day))} >}b50_transientunits))

When the above is in a Text box, the calculation is correct for a single day selection (2018-04-01, for example). When I put it as the expression in a chart, it yields -1 if only 1 day is selected.

ss1.jpg

If more days are selected, the chart will display "No data to display"

Example data (date, units):

2018-04-01, 13

2018-04-02, 53

2017-04-01, 36

2017-04-02, 23

The values I expect to see in the chart are:

Apr-01 = -63.89%  ((13-36)/36)*100

Apr-02 = 130.43% ((53-23)/23)*100

and so on...

The desired chart should look like this:

ss2.jpg

Thanks in advance for any assistance.

1 Solution

Accepted Solutions
Anonymous
Not applicable
Author

Since my data source is SQL, I was able to create a table that has the date for selection and a column for the previous year data needed. Thanks for the reply

View solution in original post

2 Replies
sunny_talwar

I suggest you to use The As-Of Table for this for best performance.... otherwise you can try using Missing Manual - Above() and Below() also... but it might get tricky because of the number of days in an year can vary....

Anonymous
Not applicable
Author

Since my data source is SQL, I was able to create a table that has the date for selection and a column for the previous year data needed. Thanks for the reply