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## How to add an avg distinct function with set analysis

Dear All,

Could someone please help me with below issue I am facing. need 4 expressions, but I am not able to succeed with the last one.

I added an attachment with the values and formula's I used.

I do a distinct count on Customer, so it gives me all unique customers per month.

In the 4th expression I want to show the average of these 12 months, so the total average of expression 3.

the average over 2014 for all unique customers is 134 (see example). I want to show this as a separate value in my 4th expression, so I can calculate deviations, etc. does anyone have an idea on how to do this?

3 Replies
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Specialist III

include a total to you last set analysis

=count(total {<[Commodity]={"Chemicals"}, Year={2014} >} DISTINCT Customer)

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Not applicable

HI Ramon,

Thanks for replying. But this formula gives me the total unique customers for 2014. and gives me value 347.

I am looking for the total average unique customers per month (even when a customer is booking each month). just like my example. the value should be 134 (average of the months 2014 as shown in expression 3).

Regards,

Bob

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Master III

No offence intended, but wouldn't the average per month be a bit strange to show in a month column?

I would make a separate chart (Pivot or Straight) to show the years and commodities in and that chart have a column to show the average per year.

The expression for a chart like that would be like this:

= avg(aggr(count(distinct Customer), Month, Commodity))

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