Dates in set analysis

[Anonymous]

Hi,

I have a metric which values doesn't accumulate over time.

Example:

In Feb-15 is 4

In Feb-16 is 5

In Apr-16 is 3

If I choose a period from Jan-16 to May-16, I want to get the value 3, that corresponds to the info of the last month available.

I have a filter for selection that corresponds to MonthYear.

I want the value of that metric in 3 forms.

Choosing May-16:

1 - Period selected (May-16) (MonthYear)

2 - Prev period of Period selected (Apr-16) (MonthYear - 1)

3 - equal period of last year of period selected (May-15) (MonthYear-12)

So I want the max date that is available (regardless selection)  that is less or equal to the period in analysis.

Example:

Choosing May-16

1 - the result correponds to the value of May-16: 3

2 - the result correponds to the value of Apr-16: 3

3 - the result correponds to the valu of Feb-15: 4

So what I'm trying to do in set analysis is:

Max({<Year=, Month=, MonthYear=, Week=, Quarter=, Date=>}MonthYear)={"<=$(Max(MonthYear))"}

Is this possible?

Can you please help me?

Thanks in advance,

Sílvia

[arthur_dom]

something like this?

=sum( {<monthYear={$(=chr(39)&monthname( max(date))&chr(39)&','&

chr(39)&monthname( addmonths(max(date),-1))&chr(39)&','&

chr(39)&monthname( addmonths(max(date),-12))&chr(39))}>} value ) ?

[Michiel_QV_Fan]

I assume you are using a master calendar.

In your master calendar you can create serial date formats.

like this: autonumber(MonthYear)          as     _MonthYear_Serial

this will generate a numeric list in which for instance this is created:

feb-15     1

feb-16      13

apr-16     15

may-16     16

Now in set analysis: sum({<_MonthYear_Serial = {$(=Max(_MonthYear_Serial ))}>}metric) will give you your results when

Selected: may-16 (_MontYear_Serial = 16)

1.     sum({<_MonthYear_Serial = {$(=Max(_MonthYear_Serial )-1)}>}metric) = apr-16 (for may-16)

2.     sum({<_MonthYear_Serial = {$(=Max(_MonthYear_Serial )-1)}>}metric) = apr-16

3.     sum({<_MonthYear_Serial = {$(=Max(_MonthYear_Serial )-13)}>}metric) = feb-15

etc.

[Anonymous]

Sorry, but can you explain what this does?

It's kind of confused to me

[Anonymous]

I Michiel,

Is there any way to do this, without going to script ?

Case my app only reloads when other person does it, and it's impossible to try this in a short time.

[martynlloyd]

Hi Silvia

Try

Max({<Year=, Month=, MonthYear=, Week=, Quarter=, Date=, MonthYear={$(Max(MonthYear))>} PutYourValueFieldHere)

Regards

Marty.

[martynlloyd]

Whoops,

Missed a curly bracket:

Max({<Year=, Month=, MonthYear=, Week=, Quarter=, Date=, MonthYear={$(Max(MonthYear))}>} PutYourValueFieldHere)

[arthur_dom]

Okay. You said you wanted to make a expression using: A- The selected period, B- the month before of the selected period, C- 12 months before the selected period. So for December, for example, it is A = Dec-2016 B = Nov-2016 anc C= Dec-2015 .

Se set analysis make possible to in an expression pass a subset (part of) a larger set.

When I wrote

Sum( {<MonthYear={"SubSet"} >} value) i am making a expression that look to that subset.

Usually you have to pass on SubSet a list of values, comma separated, and if it is string you have to add single quotes.

For your subset it was need that

Sum( {<MonthYear={'Dec-2015','Nov-2016','Dec-2016'} >} value)

then i created a expression for the subset: chr(39) is single quote, monthname formats date to month and year, and i used the date field of my application as base, i took the mas available date as base date. then I wrote for the current selection(A), the previous month (B, addmonths -1) and 12 months before (C, addmonths -12)

This is A -> chr(39)&monthname( max(date))&chr(39)&','&

This is B -> chr(39)&monthname( addmonths(max(date),-1))&chr(39)&','&

This is C -> chr(39)&monthname( addmonths(max(date),-12))&chr(39)

Lastly with this expression i told the with the dollar sign ($) to say to evaluate my expression on the subset part of the set analysis, making it.

sum( {<monthYear={$(=chr(39)&monthname( max(date))&chr(39)&','&

chr(39)&monthname( addmonths(max(date),-1))&chr(39)&','&

chr(39)&monthname( addmonths(max(date),-12))&chr(39))}>} value )

[Anonymous · Accepted solution]

Thank you all, for your help.

I did managed to get the right value using this in set analysis:

MonthYear = {">=$(=Max({<Year=, Month=, MonthYear=, Week=, Quarter=, Date=, AC_METRICA= {"Questionário de Satisfação de Colaboradores"}>} MonthYear))<=$(=Max({<Year=, Month=, MonthYear=, Week=, Quarter=, Date=, AC_METRICA= {"Questionário de Satisfação de Colaboradores"}>} MonthYear))"}

,

MonthYear={"<=$(=Max(MonthYear))"}

It's like I'm saying to, give me value, where MonthYear is the max date for that AC_METRICA, and is less than the current selection I'm making.

In the second part of the set analysis is where I choose my period (1, 2 or 3)

No matter how much time I spend in qlik with set analysis, sometimes I still get confuse, but this works so...

Again, thank you all

Sílvia