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rudywelvaert
Creator
Creator

Extra information in chart

Hello,

I'm making a bar chart based on a table that contains following columns: YEAR, CUSTOMER_ID, AMOUNT and REGION

   

YEARCUSTOMER_IDAMOUNTREGION
20130715783712,01Region A
20130450792945,51Region B
20130310382187,72Region C
20130625453946,93Region D
20140962862692,80Region A
20140072522093,59Region B
20140676261806,05Region C
20140325902217,84Region D
20150670232518,96Region A
20150413432290,54Region B
20150607762446,35Region C
20150858052914,27Region D
20160052762676,64Region A
20160257261826,88Region B
20160236112979,45Region C
20160294472115,29Region D
20170972302717,78Region A
20170913732379,84Region B
20170053362147,68Region C
20170363252872,21Region D


The dimensions of the chart are: YEAR and REGION

The expression of the chart is: AMOUNT


chart.png

I would like to add the corresponding value of the field CUSTOMER_ID to the tag

so in stead of seeing when over one of the bars

tag1.png

I want to see:

tag2.png

If it is not possible to add CUSTOMER_ID to the tag, an other way to display CUSTOMER_ID in the graph for every bar, is fine too.

I added a qvw as an example.


Thanks


R.W.


1 Solution

Accepted Solutions
RonaldDoes
Partner - Creator III
Partner - Creator III

Hi Rudy,

You can add CUSTOMER_ID as an expression.

Please find attached example.

Naamloos.png

Hope this helps you.

With kind regards,

Ronald

View solution in original post

10 Replies
sunny_talwar

Check attached

RonaldDoes
Partner - Creator III
Partner - Creator III

Hi Rudy,

You can add CUSTOMER_ID as an expression.

Please find attached example.

Naamloos.png

Hope this helps you.

With kind regards,

Ronald

kaushiknsolanki
Partner Ambassador/MVP
Partner Ambassador/MVP

Hi,

Find the attached solution.

Regards,

Kaushik Solanki

Please remember to hit the 'Like' button and for helpful answers and resolutions, click on the 'Accept As Solution' button. Cheers!
rudywelvaert
Creator
Creator
Author

Sunny,

Thanks

Answer is correct but Ronald van der Does' answer is more efficient

R.W.

rudywelvaert
Creator
Creator
Author

Kaushik,

Thanks

Answer is correct but Ronald van der Does' answer is more efficient

R.W.

rudywelvaert
Creator
Creator
Author

Ronald,

Thanks

Very efficient

R.W.

sunny_talwar

But it seems that my response is not even helpful ...

Anyways, I am glad you got what you wanted

rudywelvaert
Creator
Creator
Author

sorry I did mark it as helpful

sunny_talwar

okay