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Not applicable

Filtering on a dimension when data model has uniqueness

Hi all,

I have the following data model:

DateDimension 1Dimension 2Count Count unique
JanuaryA108
JanuaryAB129
JanuaryB21
FebruaryA128
FebruaryAB1713
FebruaryB53

I have Filters in the model for the dimensions and an expression on sum (count) and sum (count unique).

the issue is, when I choose a filter only on dimension1 = A on January I want to get the values only from the row where I have only A, and exclude from the expression the row with both A and B.

how can I do that?

Thanks,

Boris

1 Solution

Accepted Solutions
Digvijay_Singh

You are right, it is showing either extra records or grouped records. I am not finding any possibility of only setting up dimensions and achieving the requirement.

But I found the set expression condition which is generic for each expression.

Sum({<Date={'$(=GetFieldSelections(Date))'},[Dimension 1]={'$(=GetFieldSelections([Dimension 1]))'},[Dimension 2]={'$(=GetFieldSelections([Dimension 2]))'}>}Count)


I had to change nulls to '-' for proper comparison in the script.

Script added in preceding load as -

Load if(Len(Date)=0,'-',Date) as Date,

  if(Len([Dimension 1])=0,'-',[Dimension 1]) as [Dimension 1],

  if(Len([Dimension 2])=0,'-',[Dimension 2]) as [Dimension 2],

  Count,

    [Count unique];

But now I think its working as desired

select.PNG

View solution in original post

16 Replies
r3iuk
Creator
Creator

How about:

For the Count expression: ( {$-<Dimension2 = {'*'} >}Value)

For the Count Unique expression: ( {$-<Dimension2 = {'*'} >} DISTINCT Value)

Not applicable
Author

The calculations are already done in hadoop.

the question is how will the expression know which type of dimension combination I want to see.

SreeniJD
Specialist
Specialist

If I understand you correctly, you want to display data in Dimension1 when Dimension 2 is Null and vice versa..

something like.. if(isnull(dimension1),dimension2)

Regards,

Sreeni

Not applicable
Author

correct, but I will have around 6-7 dimensions, I can't write all this permutation in the expression.

SreeniJD
Specialist
Specialist

I have some rough idea.. which need to be developed..

each row will be identified by a recno() in QV... so for each of this recno() check count() of dimension which are having values.. lets say for recno()=1, if you have 6 dimensions, and you have only one dimension value corresponding to that recno() then that record can be displayed..

let me develop this and come back to you..

HTH

Sreeni

Digvijay_Singh

See if this can help -

Used - GetFieldSelections([Dimension 1],',')<>'A' in Dimension 2 enable condition. I know it is just a sample but similar thing can be tried on actual data.

hide.PNG

Not applicable
Author

Any news?

Not applicable
Author

How? I have 200 possible values for Dimension 1 , 20 Possible for Dimension 2.

Digvijay_Singh

If you are ok with the results, the same can be produced by below, in fact handles the same selection for Dim2 as well.

Dimension 1 enable condition - len(GetFieldSelections([Dimension 2]))=0 OR len(GetFieldSelections([Dimension 1]))>=1

Dimension 2 enable condtion - len(GetFieldSelections([Dimension 1]))=0 OR len(GetFieldSelections([Dimension 2]))>=1