is it possible to set up the show conditional of a list box on 2 variables?
I want to set 2 variables with 2 different buttons and if there is the right combination the list box should appeare.
With just 1 variable it works easy, but how can I handle 2?
Thanks for helping
I've tested it and the more I think about it, the less sense makes it for me to use an if statement.
The normal usage of 'Show' 'Conditional' is something like: put vVar1=1 in the field. In this case the Box is shown if the variable vVar1=1 it is not necessary to create an own if statement. But the Problem is, a connection with 'and' is also not working.
Do u have any other ideas?
it should work with 2 conditions which are connected with "and"
but other possibility would be to use a new variable which handles the state of your 2 bttuons
and the state you Need.
then us this new variable in your condition (newvar=1)
Unfortunately, the example that you show does not work, because you've only used the variables, but it does not depend of the value of the variable. Just the existance of the variable is not sufficient. In addition, the connection with and, unfortunately, does not work.
Any other ideas?
Not sure what you mean by 'Just the existance of the variable is not sufficient'. And as you mentioned, If condition is not required. If both the variables' values are numeric and something other than zero (0), then the condition becomes TRUE and the object will be visible.
Can you give more details like, what you are doing when the buttons are clicked etc. Upload a sample QVW for quick resolution.