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date

Hello all,

     i want to remove timestamp form date field as shown in an image and convert it into proper date format ,how can i achieve this ??

comunnity.png

16 Replies
SunilChauhan
Champion II
Champion II

can you attached your sample  file

Sunil Chauhan
Not applicable
Author

hi,

if my date is in MMM D YYYY h:mmTT format then it will not work.'

date field is combination of

MMM DD YYYY hh:mmTT

MMM D YYYY hh:mmTT

MMM DD YYYY h:mmTT

MMM D YYYY h:mmTT

formats

Aug 16 2013  3:56PM

Jan  2 2014 12:00AM

Jan 15 2014 12:48PM

Jan 17 2014  2:32PM

Jan 28 2014  4:22PM

Jul 31 2013  1:33PM

Jun 11 2013  5:45PM

Jun 15 2013 11:10AM

Mar  4 2014  7:06PM

Mar  4 2014  7:07PM

Nov  9 2013 12:41PM

Nov 22 2013 12:00AM

Sep 14 2013  1:35PM

Sep 30 2013  4:04PM

its_anandrjs

Hi,

It is working from my side look a script use this script

Date(Date#(UploadDate,'MMM DD YYYY hh:mmTT'),'DD/MM/YYYY') as Newdate;

//Load script

LOAD *,Date(Date#(UploadDate,'MMM DD YYYY hh:mmTT'),'DD/MM/YYYY') as Newdate;

LOAD * Inline

[

UploadDate

Aug 16 2013 3:56PM

Dec 12 2013 6:08PM

Dec 24 2013 9:07PM

Dec 28 2013 5:24PM

];

If you have sample file so provide to me

Thanks

vardhancse
Specialist III
Specialist III

Hi,

you can use DATE(FLOOR(UPLOADDATE)) AS Upload_Date

Not applicable
Author

Thank you this is what i was looking for , ya actually timestamp is string value .

Not applicable
Author

Thank you all for responding

arjunkrishnan
Partner - Creator II
Partner - Creator II

TABLE1:

LOAD * INLINE [

DATE

Aug 16 2013 3:56 PM

Jan 2 2014 12:00 AM

Jan 15 2014 12:48 PM

Jan 17 2014 2:32 PM

Jan 28 2014 4:22 PM

Jul 31 2013 1:33 PM

Jun 11 2013 5:45 PM

Jun 15 2013 11:10 AM

Mar 4 2014 7:06 PM

Mar 4 2014 7:07 PM

Nov 9 2013 12:41 PM

Nov 22 2013 12:00 AM

Sep 14 2013 1:35 PM

Sep 30 2013 4:04 PM

];

T2:

LOAD *,

Date(Date#(DATE,'MMM DD YYYY hh:mm TT'),'DD/MM/YYYY') as Newdate

Resident TABLE1;

DROP Table TABLE1;