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davoud-jelodar
Contributor II
Contributor II

problem to caculate aggrgeate value

I have a problem to caculate aggrgeate value.

I have an inline data set that includes: date, price.

LOAD * Inline [

Date    ,Price

13961030,0.672

13961101,0.682984

13961101,0.677617

13961101,0.661068

13961102,0.597959

13961102,0.617007

13961102,0.602065

13961101,0.083422

13961101,0.083526

13961101,0.080666

13961102,0.071412

13961102,0.072685

13961102,0.070975

];

I have a line graph with dim=Date and expertion is avg(price), that trendline slope is -0.1666 but if I use this expression "LINEST_M(aggr(avg(Price), Date),Date)" that show me -0.00439.

If I remove first line of inline data, everything will be OK.(remove date=13961030 and price=0.672). I do not know why? and I do not know how to fix it?

1 Solution

Accepted Solutions
davoud-jelodar
Contributor II
Contributor II
Author

Thanks for your attention.

selected Continuous Axis is not useful for my project. But your answer help me to understand what is my problem and now I solved it. I use an ID number for distinct Date, and I use "= LINEST_M(Aggr(avg(Price),ID),ID)" instead of "LINEST_M(aggr(avg(Price), Date),Date)".and now everything is OK.

View solution in original post

4 Replies
sunny_talwar

When you are looking at this in your line chart, have you selected Continuous Axis?

sunny_talwar

Check this

Capture.PNG

davoud-jelodar
Contributor II
Contributor II
Author

Thanks for your attention.

selected Continuous Axis is not useful for my project. But your answer help me to understand what is my problem and now I solved it. I use an ID number for distinct Date, and I use "= LINEST_M(Aggr(avg(Price),ID),ID)" instead of "LINEST_M(aggr(avg(Price), Date),Date)".and now everything is OK.

sunny_talwar

Super

Thanks for sharing this. Please close the thread by marking correct and helpful responses.

Best,

Sunny