problem with rank in the set analysis

[#1]

hello to all

  I'm with the following problem

have to find the greatest competitors of my client

I am using this expression

only ({<Group= {"=rank(sum([Ingresso Total] ),Grupo) 1"}>} = Group)

  and

only ({<Group= {"=rank(sum([Ingresso Total] ),Grupo) 2"}>} = Group)

  it returns me exactly what I seek, I put the two expressions in two variables.

Only then used the vTOPGrupo variables and vTOPGrupo2 respectively

sum ({<Modalidade {'Presencial'}, Group ={$(=$(vTOPGrupo2))} =>} [Total Joined])

  The problem is that some groups zeroed return and use the same expression

setting the group name that appears wrong, this way

sum ({<Modalidade {'Presencial'}, Group ={'XXX'} =>} [Total Joined])

it returns the correct value, and I'm seeing the same group

  can someone help me

[swuehl]

Your search expressions like

=rank(sum([Ingresso Total] ),Grupo) 1

don't seem right to me. Are you sure this is how they look and that's it not a typo in your post?

I would have expected something like

=rank(sum([Ingresso Total])) = 1

BTW, what is Grupo?

In anyway, your search expression doesn't return Group field  values, so you can't compare it to a modifier like {'XXX'}.

I think it would be best if you could upload a small sample application.

Regards,

Stefan

[#3]

was a mistake in typing the correct is

only ({<= {Group "= rank (sum ({<Modalidade {'Presencial'}>} = [Total Admission]), Group) = 1"}>} Group)

Grupo is group in portuguese.

in these variable

vTOPGroup =only ({<= {Group "= rank (sum ({<Modalidade {'Presencial'}>} = [Total Admission]), Group) = 1"}>} Group)

i'll return a group field value correct?

i use this variable in that expression

sum ({<Modalidade {'Presencial'}, Group ={$(=$(vTOPGroup))} =>} [Total Admission]))

That return to me the value with misses  or null ( only in a few cases

but if  the expression be like this

sum ({<Modalidade {'Presencial'}, Group ={'XXX'} =>} [Total Admission]))

being that vTOPGroup also returns me XXX

the result is right.

Sorry for the poor english is not the strong in my country

I cant make a sample because  the qvw is too big and the cases only show yourself with a huge base .

thanks Stefan

[swuehl]

I am still unsure if your expression is correct, but anyway, if vTopGroup returns the correct group e.g. when using

=vTopGroup

in a text box, I think you should write

=sum ({<Modalidade {'Presencial'}, Group ={'$(vTOPGroup)'} =>} [Total Admission]))

I am assuming you defined your variable with a leading equal sign in variable overview, right?

[#5]

I also thought it would work the same way but is not q happens.

I'm having trouble attaching the test in the forum, so I'm sending a link to the dropbox.

This same function that returns null in some other selections returns the correct value.

https://www.dropbox.com/s/x81nz76fr4k0ogt/test.qvw

[swuehl · Accepted solution]

Check attached.

[#7]

the forms of declare a function in variables and how you put into a set analysis is pretty confusing.

Thanks for your help swuehl.