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thechuy691
New Contributor II

Multiple autogenerated calendars

Hello,

I am trying to build a script that generates multiple calendars from a table given the minimun and maximun date per each row in the table. Right now I have this:

TablaDep:

LOAD * INLINE [

    TipoDep, MesesDep

    Auto, 48

    Otros, 120

];


Tabla:

LOAD * INLINE [

    IDFactura, TipoDep, Monto, Fecha

    C64079E0-A73C-4A7D-A0A6-C21636E18864, Auto, 10000,Ene 2018

    31848A13-6189-4E61-95BD-775C2BDFF296, Auto, 20000,Feb 2017

    C733D223-C797-4DE9-B3A2-B9B207E833E7, Auto, 50000,Mar 2018

    E7EBD819-3311-4145-9B6C-19DC3AE39C01, Auto, 60000,Jun 2016

    F85A59CE-F3B2-4068-9A52-D4829B9B93CF, Auto, 30000,Jun 2016

];

left join

load

TipoDep,

MesesDep

Resident TablaDep;

drop Table TablaDep;

t:

load*,

RowNo() as DepNum,

Monto/MesesDep as DepMensual,

Date#(Fecha,'MMM YYYY') as StartDate,

monthname(addmonths(Date#(Fecha,'MMM YYYY'),+MesesDep)) as FinalDate

Resident Tabla;

drop Table Tabla;

RENAME Table t to Tabla;


This created a table with the amounts I need to add to each month (DepMensual) and the start and finishing dates of the calendar, that would be: StartDate and FinalDate.


I know I can autogenerate a calendar with this:


set vMaxdate=date(AddMonths(today(),+10));

set vMindate=Date(AddMonths(today(),-15));

tempCal:

Load

$(vMindate)+iterno()-1 as tempdate,

date($(vMindate)+iterno()-1) as Date,

Monthname($(vMindate)+iterno()-1) as MonthYear

autogenerate 1  while $(vMindate)+iterno()-1<=$(vMaxdate);

But I am stock thinking how to create a loop where my variables for Mxdate and Mindate change for each rowno() and IDFactura inside my table: "Tabla". I am thinking maybe a for loop would do the job, but I cannot see how to put it together.

Thank you in advance for your help.

3 Replies
yujiyamane
Contributor II

Re: Multiple autogenerated calendars

What is your expected values in the tabla at the end?

thechuy691
New Contributor II

Re: Multiple autogenerated calendars

Hi,

I am expecting to get a single table with the concatenated auto generated calendars from each row in the original "Tabla". So I should get a table with two columns, IDFactura and Month, with 240 rows (5 original rows times 48 for each row). I am working on the for loop, and so far I have this, but it gives me an error:

FOR i = 0 to NoOfRows('Tabla')

let vStartDate= peek('StartDate',i,'Tabla');

let vEndDate= peek('EndDate',i,'Tabla');

let vNomCalendar= peek('DepNum',i,'Tabla');

let vIDFactura= peek('IDFactura',i,'Tabla');

$(vNomCalendar):

Load

$(vIDFactura) as IDDep,

Monthname($(vStartDate),+iterno()-1) as MonthYear

autogenerate 1  while $(vStartDate)+iterno()-1<=$(vEndDate);

next i

The error is that I am missing a ")", but I dont seem to see where is missing.

Thank you.

MVP
MVP

Re: Multiple autogenerated calendars

Why do you need a calendar for or from each row? Surely the calendar should start at the earliest value of StartDate, and end at the maximum value FinalDate?

T_MINMAX:

LOAD Min(StartDate) as minDate,

  Max(FinalDate) as maxDate

Resident Tabla;

Let vMaxdate = Peek('maxDate');

Let vMindate = Peek('minDate');

DROP Table T_MINMAX;

Then build the calendar using this date range.

Logic will get you from a to b. Imagination will take you everywhere. - A Einstein