below, above and set analysis problem

[#1]

Hi

I've got a table like this:

vehicleCat,vehicleNum

1,001

2,002

3,003

4,004

5,001

6,002

7,003

8,004

I need a pivot table with vehicleCat and vehicleNum as Dimension, below({$1} vehicleNum) and above({$1}vehicleNum) as Expression.

I must select a vehicleCat but i want see the below and the above vehicleNum of all the vehicleCat.

obviously above({$1}vehicleNum) doesn't work, suggestion?

[swuehl]

Try using

=aggr( below(total only({1} vehicleNum)),vehicleCat, vehicleNum)

resp.

aggr( above(total only({1} vehicleNum)),vehicleCat, vehicleNum)

as expressions.

Regards,

Stefan

[#3]

probably it works, but i haven't got much ram to see it

(my table is like the one i posted, but biiiiigger)

[swuehl]

I just noticed that you were using set identifier {$1}, not {1}.

(Well, I would probably have used {<vehicleCat=>}, {$1} is problematic if you do successive selections on vehicleCat.

Do you need to be sensitive to selections here (apart from limiting the dimension to vehicleCat)? If not, could the link to above and below be done in the script instead?

[#5]

with a selection on date it works! thank you