How to get file path of opened document from OCX object.
Hi,
I am using OCX control in our program and I need to save links to opened documents, that's why I need to get full path (or just the ServerName) of opened document in OCX control.
you can find the opened string in Me.AxQlikOCX.DocName. This is OK.
But if you try to open only “qvp://” string
AxQlikOCX.OpenDocument(“qvp://”)
a "Connect to Server" window pops-up. Here you can type your server name and choose from available documents. After clicking on "Open" button, document is opened correctly but then when I look at Me.AsQlikOCX.DocName property, there is just "qvp://". (What I was opening.)
Is there any way how to get full file path or just the server name?
I was looking in AxQlikOCX.ActiveDocument object, but I just found the FileName property (which consists of "MyDir/MyFile.qvw") and MyWorkingDirectory property (which probably holds exact path on server "C:\Dir1\Dir2\MyDir"), but I am not able to find something like "qvp://ServerName/MyDir/MyFile.qvw" or just "qvp://ServerName/" which I can concatenate with AxQlikOCX.ActiveDocument.FileName.