Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 
aveeeeeee7en
Specialist III
Specialist III

Logic Required...................!!

Dear All

Below is the Snapshot of my Requirement:

Requirement.png

Also, see the Attachments.

Regards

Av7eN

1 Solution

Accepted Solutions
petter
Partner - Champion III
Partner - Champion III

These expressions should do the trick in your second Chart:


Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"=$(=Max(CommonMonth))"}>}[Attrition Left])

Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"<=$(=Max(CommonMonth))"}>}[Attrition Left])

Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"=$(=Max(CommonMonth))"}>} ClosingMOB)

Sum({1<CommonYear={$(=Max(CommonYear))},CommonMonth={"<=$(=Max(CommonMonth))"}>} ClosingMOB ) / Max(CommonMonth)


((([Cumulative Attrition]/[Avg Closing MOB])*100)/Max(CommonMonth))*12



View solution in original post

4 Replies
aveeeeeee7en
Specialist III
Specialist III
Author

Anybody has the Answer for this........???

petter
Partner - Champion III
Partner - Champion III

These expressions should do the trick in your second Chart:


Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"=$(=Max(CommonMonth))"}>}[Attrition Left])

Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"<=$(=Max(CommonMonth))"}>}[Attrition Left])

Sum({<CommonYear={$(=max(CommonYear))},CommonMonth={"=$(=Max(CommonMonth))"}>} ClosingMOB)

Sum({1<CommonYear={$(=Max(CommonYear))},CommonMonth={"<=$(=Max(CommonMonth))"}>} ClosingMOB ) / Max(CommonMonth)


((([Cumulative Attrition]/[Avg Closing MOB])*100)/Max(CommonMonth))*12



petter
Partner - Champion III
Partner - Champion III

2015-04-16 #1.PNG

2015-04-16 #2.PNG

2015-04-16 #3.PNG

2015-04-16 #4.PNG

2015-04-16 #5.PNG

aveeeeeee7en
Specialist III
Specialist III
Author

Thank You Sir.

It's Logical.

Regards

Av7eN