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SL2
Contributor III
Contributor III

find records with same dimensions

hi everyone! I am new to Qlik sense, can anyone help me with this?

my table is looking like

SL2_1-1624057103815.png

and I want to find records with same [transaction date] and same [staff ID] but having more than 1 [cost center code],

so here entry ID 1 & 2 are records I want, and I expect to create a new field [entry I am looking for] to distinguish these entries, i.e. 

SL2_2-1624057396655.png

can anyone know how to figure this out? Thanks!

 

 

 

Labels (2)
1 Solution

Accepted Solutions
jbhappysocks
Creator II
Creator II

Hi!

Based on your example:

if(Count(total <[staff ID], [transaction date]> [cost center code])>1,'Yes','No')

(Entry 6 and 7 are also supposed to be highlighted right?)

jbhappysocks_0-1624084629607.png

If you want to create a table with only the Yes entries, like this:

jbhappysocks_2-1624085032996.png

You change it to if(Count(total <[staff ID], [transaction date]> [cost center code])>1,'Yes',Null())

and change sum(Amount) to if(Count(total <[staff ID], [transaction date]> [cost center code])>1,sum(Amount),Null())

 

and exclude Zero values.

 

If you actually want to create a new field [Entry I am looking for] and not just have it as a calculation in the table, you can add something like this to your script:

 

Join (data)
Load
"transaction date",
"staff ID",
if(count(DISTINCT "cost center code")>1,'Yes','No') as [Entry I am looking for]
Resident data Group By "transaction date","staff ID";

This will give you a field you can filter on.

jbhappysocks_0-1624086447422.png

 

 

 

View solution in original post

2 Replies
jbhappysocks
Creator II
Creator II

Hi!

Based on your example:

if(Count(total <[staff ID], [transaction date]> [cost center code])>1,'Yes','No')

(Entry 6 and 7 are also supposed to be highlighted right?)

jbhappysocks_0-1624084629607.png

If you want to create a table with only the Yes entries, like this:

jbhappysocks_2-1624085032996.png

You change it to if(Count(total <[staff ID], [transaction date]> [cost center code])>1,'Yes',Null())

and change sum(Amount) to if(Count(total <[staff ID], [transaction date]> [cost center code])>1,sum(Amount),Null())

 

and exclude Zero values.

 

If you actually want to create a new field [Entry I am looking for] and not just have it as a calculation in the table, you can add something like this to your script:

 

Join (data)
Load
"transaction date",
"staff ID",
if(count(DISTINCT "cost center code")>1,'Yes','No') as [Entry I am looking for]
Resident data Group By "transaction date","staff ID";

This will give you a field you can filter on.

jbhappysocks_0-1624086447422.png

 

 

 

SL2
Contributor III
Contributor III
Author

Thanks! I just find out if there are multiple records with same [transaction date], same [staff ID], same [cost center code] and that record would also be marked as 'Yes'. To avoid that we can make a slight change:

if(Count(distinct total <[staff ID], [transaction date]> [cost center code])>1,'Yes','No')