0 Replies Latest reply: Sep 20, 2010 1:41 PM by VMR .

# Default values on Google Maps

Hello,

I am having a problem with the auto calculation of the mid_lat and mid_long calculated by the Google Maps code example.

In my case I want to show the big picture of the map and not only one part of it (calculated by the coordinates that i have.)

Any idea how to create a default view of the map ? I supposed that i have to change something in the var_mid_lat and var_mid_long variables to make it work.

This is my code:

`// Variables required for calculating map// No need to change thesevar_pi180= '=pi()/180';var_lat_offset= '0';var_mc2= '=256*pow(2,\$(var_zoom))';var_mc1= '=256*pow(2,(\$(var_zoom)-1))';var_mid_lat= '=min(latitude)+(1+var_lat_offset)*((max(latitude)-min(latitude))/2)';var_mid_long= '=min(longitude)+(max(longitude)-min(longitude))/2';var_zoom= '=max(aggr(if(max( round(256*pow(2,(_zoom_level -1)))+( longitude *((256*pow(2,_zoom_level ))/360)) )-min( round(256*pow(2,(_zoom_level -1)))+( longitude *((256*pow(2,_zoom_level ))/360)) ) <map_size_x AND max((256*pow(2,(_zoom_level-1)))+((0.5*log((1+(sin((latitude)*pi()/180)))/(1-(sin((latitude)*pi()/180)))))*((-256*pow(2,_zoom_level))/(2*pi()))))-min((256*pow(2,(_zoom_level-1)))+((0.5*log((1+(sin((latitude)*pi()/180)))/(1-(sin((latitude)*pi()/180)))))*((-256*pow(2,_zoom_level))/(2*pi()))))<map_size_y,_zoom_level,1),_zoom_level))';var_maptype= '=if(isnull(only(maptype)),fieldvalue( '&chr(39)&'maptype'&chr(39)&', 1 ),maptype)';map_size_x= '400'; //640map_size_y= '500'; //400`