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joeybird
Creator III
Creator III

differnce in temperatures - ignore nulls

Hiya

I need to work out time difference between one date time stamp and another.

temperature of a room is taken on regular intervals during the day. This date time is recorded in the column, DateTimeTaken

=interval(max({<Temperature={'>=35'}>} DateTimeTaken) - min({<Temperature={'<=35'}>}DateTimeTaken) ,'h:mm' )

I need to calculate the time take for the room to reach 35.

sometimes the Temperature column is not filled in ''null'

please help

1 Solution

Accepted Solutions
swuehl
MVP
MVP

I guess it should be

=interval(Min({<Temperature={'>=35'}>} DateTimeTaken) - Max({<Temperature={'<=35'}>}DateTimeTaken) ,'h:mm' )

View solution in original post

4 Replies
swuehl
MVP
MVP

I guess it should be

=interval(Min({<Temperature={'>=35'}>} DateTimeTaken) - Max({<Temperature={'<=35'}>}DateTimeTaken) ,'h:mm' )

Not applicable

U can just use the max DateTimeTaken before it reached 35

=interval(max({<Temperature={'<=35'}>}DateTimeTaken),'h:mm' )

swuehl
MVP
MVP

Could you maybe post some sample lines of data and your requested result?

joeybird
Creator III
Creator III
Author

Hi

worked brill thank you x