Does anyone know how to set up a calculation in the script that looks something like this:
0.378 × Loge(x) = y
I am looking for the correct expression for Loge (log e (ln)).
I guess you're looking for the natural logarithm.
Then the answer would be
hope this helps
Thank you for answering.
Actually it is not the natural logarithm but
the natural logarithm of the e constant (Euler's constant)
The natural logarithm of a number x is defined as the base e logarithm of x:
ln(x) = loge(x)
Isn't ln(e) just 1 ?
Yes you are absolutely right.
ln(e) is just 1!
and Log() is the correct expression.
Thank you for the help Marco.
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