6 Replies Latest reply: Sep 30, 2011 5:46 AM by Jesper Almar

# Average of all first/last records

I want to calculate the average  of the first and the last record in each group described in the example below.

An average  of first/last "A" and first Last "B"

Example

 Name Sequence Value A1 1 10 A2 2 20 A3 3 15 A4 4 10 A5 5 20 Name Sequence Value B1 1 15 B2 2 10 B3 3 10 Name Sequence Value A6 1 5 A7 2 20 A8 3 30 A9 4 15 Name Sequence Value B4 1 30 B5 2 5 B6 3 10 B7 4 20

First A : AVG(10+5)

First B: AVG(15+30)

Last A: AVG(5+15)

Last B: AVG(20+20)

I can't figure out how to find the last record in a group and afterwards  find the average of all the last records.

Hope somebody can help me with an answer.

• ###### Average of all first/last records

for last recrd use

set last_var=peek('fieldname',-1,'tablename')

fisrt recard

set First_var=peek('fieldname',0,'tablename')

and then in expression

(last_var +First_var)/2

• ###### Average of all first/last records

My problem is not to find the average between the first and the last record but the average of all the first records or all the last records named A or B

Ex

Find the last record in group A1-A5

Find the last record in group A6-A9

Find the last record in group Ax-Ay

Find the average of all the results.

• ###### Average of all first/last records

Hi Jesper,

is there a way that you can determine the Group / Subgroup of records?

I.e.

A1-A5 could be Group A, subgroup 1

A6-A9 Group A, subgroup 2

B1-B3 Group B, subgroup 1

B4-B7 Group B, subgroup 2

etc..

I think you could use something like Left(Name,1) for Group and somehow the restart of indexing for subgroup increment, but do you have this information maybe already in your model?

Regards,

Stefan

• ###### Average of all first/last records

Hi Stefan

My Groups/Subgroups are well defined.

I have thousands of groups named A,

thousands of groups named B,

thousands of groups named C etc.

Each group have about 50 records.

I want to take the last record (defined bu sequence number) of each A group and then find the average of these records.

Regards

Jesper

• ###### Re: Average of all first/last records

Hi,

what I wanted to say was, how could we tell QV which Names belong to a subgroup? Sequence numbers are not unique.

I assume your names are ascending with Sequence numbers, so if e.g. A6 has a lower sequence number than A5, this will indicate that it belongs to a different subgroup, starting a new sequence numbering.

I think if we had something like a subgroup index, that would make life much easier, since we can look for min and max sequence then per subgroup index.

I assume you don't have this in your model, so let's create an index:

Groups:

Name,    Sequence,    Value

A1,    1,    10

A2,    2,    20

A3,    3,    15

A4,    4,    10

A5,    5,    20

B1,    1,    15

B2,    2,    10

B3,    3,    10

A6,    1,    5

A7,    2,    20

A8,    3,    30

A9,    4,    15

B4,    1,    30

B5,    2,    5

B6,    3,    10

B7,    4,    20

];

Left(Name,1) as Group,

if (peek(Sequence)=Sequence-1 and previous(Left(Name,1))=Left(Name,1), peek(Subgroup), rangesum(peek(Subgroup))+1) as Subgroup

resident Groups order by Name asc;

I assumed that your Groups are given by the first letter, probably that is simplying your real situation, so just use anything else to retrieve your Groups here (Group means the class for which you want to average the results later on). For example, use Keepchar(Name) instead of left().

Now we are having Groups and subgroups, we can calculate the average of first and last sequences per subgroup and within groups like

=avg(aggr(FirstsortedValue(Value,Sequence),Group,Subgroup))

for averaging the first sequence number values and

=avg(aggr(FirstsortedValue(Value,-Sequence),Group,Subgroup))

for averaging the last sequence number values.

(See also attached app. I put above two expression in a straight table with dimension Group).

Regards,

Stefan

• ###### Re: Average of all first/last records

Hi Stefan

Your suggestion seems to work for me.

Thanks a lot for your help.

Best Regards

Jesper