3 Replies Latest reply: Jan 22, 2012 4:22 AM by Jean-Pierre Bakhache

# Expression link with 2 colums from 2 tables

Hi,

I Have 2 tables linked with one column

Invoice

fam_num

residence_ num_invoice

Residence

fam_num

residence_num

I am trying to make a chart where the residence_num_invoice = residence num

The expression I am using is given below:

sum({<[RESIDENCE_NUM_INVOICE]=[RESIDENCE_NUM]>}ENTREE)

But I get Result = 0

When I am replace RESIDENCE_NUM by a number that exists, all is right

sum({<[RESIDENCE_NUM_INVOICE]={4117}>}ENTREE) for example

What's the problem in the first expression ?

Any help would be greatly appreciated.

• ###### Expression link with 2 colums from 2 tables

hi,

maybe something like this might help:

Sum(If(RESIDENCE_NUM_INVOICE = RESIDENCE_NUM, ENTREE, 0))

• ###### Expression link with 2 colums from 2 tables

Thanks

That's work but I don't understand why it dosn't work with the the expression

sum({<[RESIDENCE_NUM_INVOICE]=[RESIDENCE_NUM]>}ENTREE)

• ###### Expression link with 2 colums from 2 tables
This is because the expression assumes that a selection was made in the field RESIDENCE_NUM so you can compare it to RESIDENCE_NUM_INVOICE (otherwise it returns Null).
That's why it worked when you passed a real value {4117}, and will also work if you select that value from a listbox.
Your expression can work when using the Possible values function P() like this:
I tried with a very simple scenario:

t1:
fam_num, residence_num_invoice, entree
1,1123,55
1,2233,40
2,1132,45
2,3344,122
3,2535,500
]
;

t2:
fam_num, residence_num
1,1111
1,1123
2,1132
2,4433
]
;
and using this as expression in a pivot table having fam_num as dimension:

sum({\$<residence_num_invoice = P({\$} residence_num)>} entree)

and i got same result as the expression with the if condition.
you might have to switch between both of above fields depending on your case, just try to see which one gives you your desired result.
Hope i was able to explain at least what i know .