1 Reply Latest reply: Jan 18, 2015 11:56 PM by Ramkumar V RSS

    How to get file path of opened document from OCX object.

      I am using OCX control in our program and I need to save links to opened documents, that's why I need to get full path (or just the ServerName) of opened document in OCX control.
      If I open some document:
      you can find the opened string in Me.AxQlikOCX.DocName. This is OK.

      But if you try to open only  “qvp://”  string
      a "Connect to Server" window pops-up. Here you can type your server name and choose from available documents. After clicking on "Open" button, document is opened correctly but then when I look at Me.AsQlikOCX.DocName property, there is just "qvp://". (What I was opening.)
      Is there any way how to get full file path or just the server name?
      I was looking in AxQlikOCX.ActiveDocument object, but I just found the FileName property (which consists of "MyDir/MyFile.qvw") and MyWorkingDirectory property (which probably holds exact path on server "C:\Dir1\Dir2\MyDir"), but I am not able to find something like "qvp://ServerName/MyDir/MyFile.qvw" or just "qvp://ServerName/" which I can concatenate with AxQlikOCX.ActiveDocument.FileName.