2 Replies Latest reply: Nov 12, 2012 6:07 AM by steve peroni RSS

    include statement with a variable

    steve peroni

      Hi,

      is there a way to inser a variable path into an include statement ?

       

      I'm trying this:

       

      let my_include = '$include=' & peek('my_path');

       

      $(my_include);

       

      but simply it doesn't work, without any further.

       

      Is it possible to do it ? Help please

       

      Thanks in advance