Greetings everyone,
I have a container object that has 3 tables inside, am trying to export only the selected table to csv, however currently its exporting all the object under the container which is the 3 tables, I know the reason for that is because its inside a for loop on the objects of the container, however my question is how can I get only the active object from inside the container?
I found another post mentioning "app.getFullPropertyTree" however am not sure how to use it.
Is there a way to tell which object is currently selected inside the container, then passign that objectID to the export csv funtion?
my current code:
app.visualization.get('TjAb').then(async function (vis) {
vis.show("QV01");
visList.push(vis);
const mainId = vis.id;
const containerLayout = await vis.model.getLayout();
const childObjects = Object.values(containerLayout.qChildList);
for (const child of childObjects) {
for (const item of child)
{
const objectexport = await app.visualization.get(item.qInfo.qId);
attachExportEvent(mainId, objectexport, item.qInfo.qId);
}
}
});
function attachExportEvent(mainId ,object, objectId) {
$(`#buttonID`+ mainId).click(async function () {
activeObject = object;
console.log("exporting object " + activeObject);
if (activeObject) {
activeObject.exportData({ format: 'CSV_C', state: 'A' }).then(function (link) {
window.open(link);
});
}
});
}
