# App Development

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Contributor III

## Number of Rows that have a Value

How do I get the number of rows that have a value in a dimension?

I have tried:

Sum(Aggr(Count(DISTINCT {<ExpectedCases = {'*'}>} OperatorName),OperatorName))

noofrows(column(1))

Sum(if(isnum(\$(vEC))=-1,1,0))

max(rank(total column(1))

What I'm trying to do is modify this formula

(rank(total column(1))/(noofrows(TOTAL)/2))-1

so that denominator is number of records in the dimension that have a value instead of the total records in the dimension.

Please let me know if you have any questions.

20 Replies
MVP

But this should give you 27, right?

Count(TOTAL DISTINCT {<ExpectedCases = {'*'}>} Employee)

If not, then try this

Aggr(NODISTINCT Count(DISTINCT {<ExpectedCases = {'*'}>} Employee), Factory)

Contributor III
Author

Count(TOTAL DISTINCT {<ExpectedCases = {'*'}>} Employee) gives me 7, which is the distinct number of employees on the unique factory/line/shifts in the data.

Aggr(NODISTINCT Count(DISTINCT {<ExpectedCases = {'*'}>} Employee), Factory) also gives me 7.

MVP

‌Remove DISTINCT from within Count

Contributor III
Author

That also returns 7.  Which makes sense since there's 7 operators in the data.  Should there be a count of operators aggregated over factory, line, shift?

MVP

This returned 7 also?

Count(TOTAL {<ExpectedCases = {'*'}>} Employee)

Contributor III
Author

Yes it did.

MVP

Count(TOTAL {<ExpectedCases = {'*'}>} Employee&Shift&Line&Factory)

Contributor III
Author

That returns 5239.  I don't know what that result means.

MVP

Count(DISTINCT TOTAL {<ExpectedCases = {'*'}>} Employee&Shift&Line&Factory)

Contributor III
Author

That worked!  I can't believe it!  Thank you!  Thank you!  Thank you!

This also works, Count(TOTAL DISTINCT {<InspectedCount = {'*'}>} PlantName&LineName&ShiftNumber).

So this reason this works is I'm counting the total distinct operators that have data across each unique dimension.

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