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Hello,
I have the following issue. Below a pivot table with backlog information of open orders. On week / day dimension you can see how many orders are open (Backlog End of Day). The open orders are the result of the created minus the invoiced order amount within the same time dimension.
What I want to realize is the backlog on the end of each week.The result will be
7-6-2015 = 10500
14-6-2015 = 52705
21-6-2015 = 455
etc
What the correct set analysis for this problem?
Thanks
Robert
WeekY | Date | Creation | Invoiced | Backlog End of Day |
---|---|---|---|---|
2015/23 | 4-6-2015 | 10500 | 0 | 10500 |
5-6-2015 | 0 | 0 | 10500 | |
6-6-2015 | 0 | 0 | 10500 | |
7-6-2015 | 0 | 0 | 10500 | |
2015/24 | 8-6-2015 | 0 | 10500 | 0 |
10-6-2015 | 16841 | 16841 | 0 | |
11-6-2015 | 52705 | 0 | 52705 | |
12-6-2015 | 0 | 0 | 52705 | |
13-6-2015 | 0 | 0 | 52705 | |
14-6-2015 | 0 | 0 | 52705 | |
2015/25 | 15-6-2015 | 10880 | 63585 | 0 |
18-6-2015 | 455 | 0 | 455 | |
19-6-2015 | 0 | 0 | 455 | |
20-6-2015 | 0 | 0 | 455 | |
21-6-2015 | 0 | 0 | 455 | |
2015/26 | 22-6-2015 | 0 | 0 | 455 |
23-6-2015 | 3418 | -782 | 4655 | |
24-6-2015 | 29000 | 455 | 33200 | |
25-6-2015 | 12130 | 33200 | 12130 | |
26-6-2015 | 3744 | 0 | 15874 | |
27-6-2015 | 0 | 0 | 15874 | |
28-6-2015 | 0 | 0 | 15874 | |
2015/27 | 29-6-2015 | 16675 | 0 | 32549 |
30-6-2015 | 643 | 16675 | 16516 |
The correct set analysis solution is not using any. See attached example.
Hi Gysbert,
Which example attachment??
The one I attached in my previous post of Aug 19, 2015 11:13 AM: