I guess you always have to read all records that you want to store into 1 qvd (reading your initial records, concatenate new ones then storing into qvd).
However in your case, if you always need to insert new records (no update/delete of existing record), you could store each time the new pack of records into a different qvd and choose a common name for them with the timestamp (date and/or time), say MyQvd20141006.qvd and MyQvd20141007.qvd, etc.
You can use a variable for that:
let vDate = date(today(), 'YYYYMMDD');
And after loading your new records:
store MyQvd into MyQvd$(vDate).qvd;
When you want read the qvds that start with "MyQvd":
Thanks for quick response. I am aware of all those stuff which u had mentioned above.
My query/question is whether I can insert changed/new 100 records directly in dataqvd.qvd without doing the process which is mentioned in 1st discussion
I already mentioned that you need to do the process you described if you want to store in 1 qvd only.
As far as I know, there's no insert/concatenate functionality directly into a qvd, without passing by a resident load.
I also proposed an alternative if you want to avoid doing your process, by storing into different qvds which names start the same, so you can later use the wildcard character '*' when you want to load the whole data.
