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Hello everyone!
Do you have any way to total the column "Acumulado".
Produto | Atual | Anterior | Acumulado | Acumulado - correct |
684 | - | - | 5273 | |
A | 11 | - | 11 | 11 |
B | 76 | 11 | 87 | 87 |
C | 10 | 76 | 97 | 97 |
D | 24 | 10 | 121 | 121 |
E | 82 | 24 | 203 | 203 |
F | 38 | 82 | 241 | 241 |
G | 8 | 38 | 249 | 249 |
H | 74 | 8 | 323 | 323 |
I | 95 | 74 | 418 | 418 |
J | 41 | 95 | 459 | 459 |
K | 82 | 41 | 541 | 541 |
L | 41 | 82 | 582 | 582 |
M | 38 | 41 | 620 | 620 |
N | 17 | 38 | 637 | 637 |
O | 47 | 17 | 684 | 684 |
I've attached the fixed .qvw.
What I did:
Have to be in the expression.
I'm not sure what you want. What I did gives the results that you wanted in your first post...
I need the sum of the expression SUM(Acumulado).
You need it where? It does exist on the table (if you do what I have in my above post) if that's where you want it...
I really need the sum in the expression.
friend, a question like you did that colummna earlier, if I can pass the code, please
This expression is not solved my case, but it works.
if
(Dimensionality()=0,noofrows()*((Count(distinct DATA)+1)/2), RowNo(total
))