Wildmatch Function

[#1]

Is there a way to check the string if it is preceded by a number?

For example:

String = "1234 abcdefg"

Wildmatch(String,'*# abcd*') > 0

[senpradip007]

Try to use like 

String = "1234 abcdefg"

=WildMatch(String,  '*abcd*')

[anbu1984]

=If(IsNum(Left('1234 abcdefg',1)),'Num','Not Num')

=If(IsNum(SubField('1234 abcdefg',' ',1)),'Num','Not Num')

[#4]

I Used Wildmatch(String, '?????abcd*') > 0 instead.

[anbu1984]

This expr returns true even if you have alphabets

Wildmatch('abcd abcd', '?????abcd*') > 0