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Hi ,
Below is the table
Tab:
Date1 Date2 Id
01/01/2016 01/05/2016 01
01/02/2016 01/09/2016 02
01/04/2016 01/12/2016 03
02/02/2016 04/05/2016 04
03/05/2016 02/01/2016 05
04/06/2016 01/15/2016 06
04/27/2015 03/14/2016 07
03/03/2016 03/05/2016 08
above two dates from two different tables (tab1: contains date1 and id && tab2: date2 and id) are linked to master calender . now. i need network days between date1 and date2 if i select month .
example:
if i select jan, then i need to pull all jan month records and see if the network days between those two dates is less 5 then show the id.
Thanks,
anusha
example:
if i select jan, then i need to pull all jan month records and see if the network days between those two dates is less 5 then show the id.
How have you linked the two field to a single master calendar where you chose the month from?
sorry .. its two tables ...
tab1: contains date1 and id
tab2: contains date2 and id
both the two tables are joined on id and i have created a link table to link date with master calender ..
Maybe like Attached
Thanks....
but , i need id whose difference of dates excluding weekend <5 for a particular month .
What's exactely wrong with the solution settu_periasamy suggested?
I've noticed that some id shows date1 after date2, so you may need to check this
=if(NetWorkDays(Date1,Date2)<5 and Date1<= Date2, Only(Id))
And Networkdays() will count working days including both start and end, so you may want to add +1 to the start date:
=if(NetWorkDays(Date1+1,Date2)<5 and Date1<= Date2,Only(Id))
Hi,
i used the below logic considering start date is less then end date .
if(NetWorkDays('$(vAb1)','$(vAb)')>5, only(id)) or if(NetWorkDays('$(vAb1)','$(vAb)')<5, only(Key4))
but when i select any month .. i getting count 0 for both of them ..
Kindly help me ..
Where does Key4 field come from?
If you want to calculate the absolute difference between the two dates:
=if(NetWorkDays(RangeMin(Date1,Date2),RangeMax(Date1,Date2))<5, Only(Id))
key4 is id ..
if(NetWorkDays('date1','date2')>5, only(id)) or if(NetWorkDays('date1','date2')<5, only(id))
thanks,