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Date stamp conversion

Hi, I'm battling to convert this raw data into a normal date.

here is an example of the date stamp (CreatedDate field) import:  "2015-06-11T09:45"

I want to convert this to just the normal date like this:  "2015/06/11".

Please assist with syntax for this.

Many thanks

Labels (1)
1 Solution

Accepted Solutions
sunny_talwar

Try this:

Date(Date#(Left(CreatedDate, 10), 'YYYY-MM-DD'), 'YYYY/MM/DD') as Date

View solution in original post

8 Replies
sunny_talwar

Try this:

Date(Date#(Left(CreatedDate, 10), 'YYYY-MM-DD'), 'YYYY/MM/DD') as Date

Not applicable
Author

Perfect!  Thanks

jagan
Partner - Champion III
Partner - Champion III

Hi,

You can also try like this

LOAD

*,

MakeDate(SubField(CreatedDate, '-', 1), SubField(CreatedDate, '-', 2), SubField(CreatedDate, '-', 3)) AS Date

FROM DataSource;

Hope this helps you.

Regards,

jagan.

HirisH_V7
Master
Master

Hi,

Check this,

Replace(SubField(Field,'T',1),'-','/')

HTH,

Hirish

HirisH
senpradip007
Specialist III
Specialist III

Try like:

date(Timestamp#(replace(CreateDate, 'T', ' '), 'YYYY-MM-DD hh:mm'), 'YYYY/MM/DD') as NewDate

tamilarasu
Champion
Champion

Also try,

Date(Date#(PurgeChar(CreatedDate,'T'),'YYYY-MM-DDhh:ss'),'YYYY/MM/DD')

                                                  OR

Date(Date#(Replace(CreatedDate,'T',''),'YYYY-MM-DDhh:ss'),'YYYY/MM/DD')

engishfaque
Specialist III
Specialist III

Dear Manus,

Here is a script for timestamp conversion

Table1:

LOAD *, Date(Left(Date, Index(Date, 'T') - 1), 'YYYY/MM/DD') as newDateField Inline [

  Date

  2015-06-11T09:45

];

For more detail, kindly find attached App.

Kind regards,

Ishfaque Ahmed

oknotsen
Master III
Master III

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