include statement with a variable

[Anonymous]

Hi,

is there a way to inser a variable path into an include statement ?

I'm trying this:

let my_include = '$include=' & peek('my_path');

$(my_include);

but simply it doesn't work, without any further.

Is it possible to do it ? Help please

Thanks in advance

[flipside · Accepted solution]

Hi,

Try it this way ...

let my_include= 'LoadScript.txt';

$(include=$(my_include));

flipside

[Anonymous]

THANKS VERY MUCH !!!