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Hello,
I have a table with a ordernumber and two additional columns with Starttime and Finishtime.
I used following function for showing me the timedifference (duration) of the ordernumber :
=sum(interval(FinishTime-StartTime,'mm.ss')) shows me the duration in minutes and seconds.
Now I need a additional column for the average duration of all selected ordernumbers.
I tried putting the avg function or divide the formula through the distinct counts of orders, but still getting wrong values.
I need that for a additional column and for a kpi window.
I hope someone knows a proper solution.
Thank you very much in advance.
Hi,
most probably you won't get any replies if you don't put some basic additional information:
- sample data
- what is wrong
- what is expected
Hello ,
I agree, should have put more data.
Here I have a sample table:
Ordernumber | Starttime | Finishtime | Duration |
|
12345 | 06.07.2020 09:15:48 | 06.07.2020 09:21:36 | 05.47 |
|
23456 | 07.07.2020 12:37:38 | 07.07.2020 12:38:55 | 01.17 |
|
78954 | 07.07.2020 12:44:17 | 07.07.2020 12:44:23 | 00.05 |
|
45621 | 24.08.2020 13:37:59 | 24.08.2020 13:38:40 | 00.41 |
|
So here I have example of orders and each order has to be prepared in a process. That will be documented with a starttime and a finishtime. For calculating the duration which is the subtraction of Finishtime - Starttime in the format of minutes and seconds, I use the interval()-funcion:
=interval(FinishTime-StartTime,'mm.ss')
Now I need a additional column and kpi-window which showes me the avg duration time of the ordernumbers that I want to select.
The following function gives me as expected the sum of durationtime of the selected orders properly:
=sum(interval(FinishTime-StartTime,'mm.ss'))
So I when I need the average time of all selected orders I would expect the following to work:
=avg(interval(FinishTime-StartTime,'mm.ss'))
But instead I get these weird numbers:
Ordernumber | avg(interval…. |
12345 | 0,004027431 |
23456 | 0,000898148 |
78954 | 6,55E-05 |
45621 | 0,000476458 |
Hope I explained my problem better this time.
Thank you in advance.