App Development

[pasgalbarra]

Hi Community,

I need to count the consecutive times that I have a "e" value, I managed to add the 1/0 value but now I need to sum these values.

I need to count the consecutive times I have a 1, but when I have a 0 I need to start again, any Ideas on how can I do it?

Thanks

[rubenmarin]

Hi, if prev_read is the label of the last expression an is calculated as:

If(Above(TOTAL START_READ_TYPE)='e',1,0)

The accumulation could be:

If(Above(TOTAL START_READ_TYPE)='e',Above(TOTAL [prev_read])+1,0)

It will be flagged as an error but it should work

[pasgalbarra]

Hi @rubenmarin ,

Thanks for your answer, it;s not working as I expect, as you can see it shows always 2, but I am expecting..3,4,5,6 in these rows

[rubenmarin]

This expression was to sustitute the prev_read expression, for this to work this expression needs to be labeles as prev_read, or change the expression and the label so it uses the previous value if this same expression.

It always shows 2 because there is other prev_read expression with 0 or 1.

[pasgalbarra]

prev_read is created in the script using:

,If(START_READ_TYPE = 'e' and Peek([START_READ_TYPE]) ='e', 1,0) as prev_read

[rubenmarin · Accepted solution]

Then set the label of this expression prev_read2 and use:

If(Above(TOTAL START_READ_TYPE)='e',Above(TOTAL [prev_read2])+1,0)

[pasgalbarra]

@rubenmarin  Thanjs man!