If there is no value '1', then pick '2'

[Femke_DPG]

Hi experts

I have a question on which I do not find an answer online. 

When value '1' does not exist, it has to take '2' in the set analysis of a calculation. If 1 does exist, it has to take '1'.

I had made a new dimension in the load editor, but it is not correct.

if(Min([Position Group])='2', '1',[Position Group]) as TEST

In this example '1' exists as position group and in TEST it takes value '1' 2 times, while in this example it has to take just value '1' because it exists. It counts dubble when I use '1' in set analysis:

In this example it is correct, because there is no value '1' in the column 'position group' and 2 became 1:

Thank you for helping me out! 

Femke

[JHuis]

Hello,

can you give me the values what you are trying to do in the last colum?

Brodcast Date	Break label	Position group	TEST
2022-01-02	A85	3-98
2022-01-02	A85	1
2022-01-02	A85	2
2022-01-02	A85	99
2022-01-02	A85	100