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This is my current calculation:
column(7)/column(11)
Usually I would utilize an if statement like this:
If (column(7)/column(11)>0,column(7)/column(11),'')
Which would show all available numbers over 0. However this expression doesn't work as expected.
So was wondering if it is possible to achieve something similar with a different approach.
Thankyou
Instead an if-loop you may try something like:
rangemax(column(7)/column(11), 0)