Set Analysis - Exclude Selections Except

[mrainey18]

Two things:

1) We recently upgraded to the latest release of Qlik Sense and we have and some problem with the Set Analysis doing the same thing from 3.2 to now.  Were there any big changes to how Qlik Sense reads the Set Analysis code?

2) I know how to "Include all selections except":

     sum( {<CostCenterName= , CostCenterID= >} $(vSales))

Is there a way to do it the other way?

     sum( total {<SIC= >} $(vSales))

That doesn't work.

I have a Pivot Table with Rows of CostCenterName and the SIC.  Measure is sum($(vSales)).

I want to add another measure finding the percentage of sales that cost center does for each SIC they sell towards.

Example:

Cost Center: Baltimore

SIC: Clothing

Sales for Baltimore: 100k

Sales for Baltimore Clothing: 5500

Sales for Clothing: 200k

Total Sales: 10M

Baltimore Total %: 1%

Baltimore Clothing %: 2.75%

Displayed Like this in a pivot table:

Baltimore                              100,000                         1%

     Clothing                            5500                              2.75%

Message was edited by: Michael Rainey Added Test Output

[sunny_talwar]

So you are looking to ignore everything except SIC? May be this

Sum({1<SIC = p(SIC)>} $(vSales))

or this

Sum({1<SIC = $::SIC>} $(vSales))

[YoussefBelloum]

hi,

can you attach some some lines of your table ?

[mrainey18]

Sum({1<SIC = p(SIC)>} $(vSales))

or this

Sum({1<SIC = $::SIC>} $(vSales))

I think you had an extra }

Either way this comes back blank/null.

[mrainey18]

Here is my code:

Sum({1<SICName = $::SICName, SIC= $::SIC}>} $(vSales))

or

Sum({1<SICName = p(SICName), SIC= p(SIC)}>} $(vSales))

Tried both, both returns nulls.

[mrainey18]

Unfortunately I can not. 

[sunny_talwar]

Yes, I did have an extra } in both my expression... and so do you... can you try this

Sum({1<SICName = $::SICName, SIC= $::SIC>} $(vSales))

or

Sum({1<SICName = p(SICName), SIC= p(SIC)>} $(vSales))

[mrainey18]

Woopse!  Thank you.  This does show information but its also dividing it by Cost Center

So instead of:

Baltimore                              100,000                          1,000,000

     Clothing                            5500                              200,000

It shows:

Baltimore                              100,000                         100,000

     Clothing                            5500                             5500

[mrainey18]

So I change it to CostCenter and that didnt work either:

Sum({1<CostCenterName = $::CostCenterName, CostCenter = $::CostCenter >} $(vSales))

[sunny_talwar]

May be adding total... not entirely sure but may be this

Sum(TOTAL {1<SICName = p(SICName), SIC= p(SIC)>} $(vSales))