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bigdataxhi
Contributor
Contributor

Convert Julian date

Hi all,

I hope you can help with this quick query.

In my data I have several date fields. The format of the dates is (from what I can see) "Julian" dates set as 7 digits:

YYYY[day of the year in 3 characters]

Samples:

Date_of_Birth

1965166
1970259
1965063

Please can you help with a load script for this Date_of_Birth field, converting the above to "normal" dates in DD/MM/YYYY?

Many thanks!

1 Solution

Accepted Solutions
Anil_Babu_Samineni

What does the date you are expecting for this? 1965166

May be this?

=TimeStamp( MakeDate( Floor(Date_of_Birth / 1000) ) + 1000 * Frac(Date_of_Birth / 1000) -1 )

Or

=Timestamp(Date_of_Birth /24/60/60s

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful

View solution in original post

4 Replies
Anil_Babu_Samineni

What does the date you are expecting for this? 1965166

May be this?

=TimeStamp( MakeDate( Floor(Date_of_Birth / 1000) ) + 1000 * Frac(Date_of_Birth / 1000) -1 )

Or

=Timestamp(Date_of_Birth /24/60/60s

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful
sunny_talwar

May be like this?

Table:

LOAD Date_of_Birth,

  Left(Date_of_Birth, 4) as Year,

  Right(Date_of_Birth, 3) as Days;

LOAD * INLINE [

    Date_of_Birth

    1965166

    1970259

    1965063

    1965001

];

Left Join (Table)

LOAD Date_of_Birth,

  IterNo() as Days,

  Date(MakeDate(Year) + IterNo()-1) as Date

Resident Table

While YearStart(MakeDate(Year)) + IterNo() <= YearEnd(MakeDate(Year));

sunny_talwar

Wow this is much simpler

bigdataxhi
Contributor
Contributor
Author

Perfect, thanks!