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Hello QV Community,
I am having a problem with QV cooperating the way I want in a pivot table I am building. I am doing some analysis with Medical Claims utilization for a particular group of members and want to show some metrics for particular utilization types. For many of my calculations, I need to use the total members as the denominator but QlikView is just showing the sum of the members that had a claim of that particular type. My member counts are listed on a separate table than my claims table.
Does anyone have any suggestions to correct this? I essentially need QV to ignore the utilization type when totaling membership in this pivot table (thus making the value a constant for each row).
Thanks for any help anyone can provide!
Have your tried something like Sum(TOTAL Members)
can u post some sample data ?
Here is what is happening:
Claim Code Members
001 10
002 20
003 15
004 10
Total 55
Here is what I want it to show:
Claim Code Members
001 55
002 55
003 55
004 55
Total 55
I don't want QV to divide membership up by Claim Code (again, claims info is on one table and my membership info is on another). I need to show some % of total calculations on each line so that is why I need membership in total.
Here is what is happening:
Claim Code Members
001 10
002 20
003 15
004 10
Total 55
Here is what I want it to show:
Claim Code Members
001 55
002 55
003 55
004 55
Total 55
I don't want QV to divide membership up by Claim Code (again, claims info is on one table and my membership info is on another). I need to show some % of total calculations on each line so that is why I need membership in total.
Have your tried something like Sum(TOTAL Members)
use sum(total Members)
Thanks. This worked. I thought I already tried a sum total but I guess not.
I am new to QV so forgive me for the easy question!
Hi,
Did you try with TOTAL ?
ex :
count(TOTAL Member_Id)
or
sum(TOTAL Member_Field)
Hi,
there is no silly question. So dnt be sorry. we'all are learning here.
dnt frgt to Mark Answered
You just made the question difficult![]()
Regards
Thanks everyone. All of these answers were correct. I marked correct answer for Nigel's response. Appreciate the quick feedback.