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Anonymous
Not applicable

Market Evolution Index Calculation

I need to calculate a market evolution index (EI 2014) based on the following data:

Screen Shot 2015-10-28 at 01.12.43.png

The (EI 2014) for the subgroup "DIRECT ACTING ANTIVIRALS" is calculated as follows:

EI 2014 = (100 + % Growth Rate '14 for the Subgroup) / (100 + Total % Growth Rate '14) * 100      which is

EI 2014 = (100 + 13.47) / (100 +26.76) * 100 = 89

A value under 100 means that the subgroup is growing less than the overall market.

How can i accomplish this with an expression in Qlikview?

1 Solution

Accepted Solutions
manojkulkarni
Partner - Specialist II
Partner - Specialist II

17 Replies
swuehl
MVP
MVP

That's hard to answer without knowing how your expressions look like.

Assuming the percentages are really percentages, i.e. 13.47% is 0.1347, and assuming your % growth rate 14 column is based on a field [% Growth '14] in the data model, your expression could look like

= (1 + Only([% Growth '14]) ) / (1 + Avg(TOTAL [% Growth '14])) * 100

Probably my assumptions are all wrong...

MarcoWedel

please post a sample application.

regards

Marco

Anonymous
Not applicable
Author

Thanks Swuehl

The [% Growth '14] is a calculated column

Anonymous
Not applicable
Author

Many thanks Marco

i will create a sample application as the original one is too big.

Regards.

Anonymous
Not applicable
Author

Marco

Please find attached sample application.

Regards.

manojkulkarni
Partner - Specialist II
Partner - Specialist II

try to use TOTAL in first 2 expressions to get the Total Growth.

Not applicable
Author

Hi Christopher,

Try the below expression

=(100 +([% Growth '13]*100))/( (100 +((Sum (TOTAL {$<Year={2013},Month=>} QTY)/Sum (TOTAL{$<Year={2012},Month=>} QTY))-1)))*100


Regards

Anand

Not applicable
Author

Hi Christopher,

Try the below expression

=(100 +([% Growth '13]*100))/( (100 +((Sum (TOTAL {$<Year={2013},Month=>} QTY)/Sum (TOTAL{$<Year={2012},Month=>} QTY))-1)))*100

Not applicable
Author

Hi Christopher

Find the application with solution.

Regards,

Anand