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smilingjohn
Specialist
Specialist

Not isnull

Hi Community,

I am trying to acheve the count of ID's  when two or one field is is not  null or not empty  for which i am using the below formula which is not giving me proper result . 

Can someone please correct me on this. 

if(not IsNull(DeptID) or not IsNull(CustomID),Count({<Region={'Newyor'},Priority={'High','Medium'}>}SalesID)).

 

Thanks

1 Solution

Accepted Solutions
Anil_Babu_Samineni

Perhaps this?

if(Len(DeptID&CustomID)>0 ,Count({<Region={'Newyor'},Priority={'High','Medium'}>}SalesID))

Or

Set Analysis

Count({<Region={'Newyor'},Priority={'High','Medium'}, SalesID={"=Len(DeptID&CustomID)>0"}>}SalesID)

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful

View solution in original post

5 Replies
Anil_Babu_Samineni

Perhaps this?

if(Len(DeptID&CustomID)>0 ,Count({<Region={'Newyor'},Priority={'High','Medium'}>}SalesID))

Or

Set Analysis

Count({<Region={'Newyor'},Priority={'High','Medium'}, SalesID={"=Len(DeptID&CustomID)>0"}>}SalesID)

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful
smilingjohn
Specialist
Specialist
Author

Thanks for the reply @Anil_Babu_Samineni 

sorry to say that your expression above is not working . 

I tried both the expression but i dont get the expected result 

 

Chanty4u
MVP
MVP

can you try this?

Count({<Region={'Newyor'},Priority={'High','Medium'}, SalesID={"=Len(trim(DeptID&CustomID))>0"}>}SalesID)

 

Anil_Babu_Samineni

@smilingjohn  If my expression not working, Why did you accepted my solution? If you have another work around, You can put that and mark that as answer ..

Best Anil, When applicable please mark the correct/appropriate replies as "solution" (you can mark up to 3 "solutions". Please LIKE threads if the provided solution is helpful
smilingjohn
Specialist
Specialist
Author

@Anil_Babu_Samineni  Your second expression did work , and thats the reason i marked it as accept solution . 

Thanks